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★ Logarithmic Reductions ★

[tex]3 + 4 {e}^{x + 1} = 11 \\ 4 {e}^{x + 1} = 11 - 3 \\ 4 {e}^{x + 1} = 8 \\ {e}^{x + 1} = 2 \\ applying \: log_{e} \: to \: both \: the \: sides \\x + 1 = ln2 \\ x = ln2 \: - 1[/tex]


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