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16-02-2018
Mathematics

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calculate y when dy/dx=1/(6x+5)^3

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16-02-2018

dy/dx = 1/(6x + 5)^3

dy/dx = (6x + 5)^-3

Using the linear extension of the algebraic integral we have

y = 1/6 * (6x + 5)^(-3+1) / (-3+1)

= 1/6 * 1 / (6x + 5)^2 / -2

= - 1 / [12(6x + 5)^2 ] + C ( where C is constant of integration)

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