Answer: [tex]\frac{1}{20}[/tex]
Step-by-step explanation:
Given: The total number of runners run on the same cross country team = 5
If Alice is chosen first and Emma is chosen second, then the number of ways to choose two players =[tex]1\times1=1[/tex]
The total number of ways to choose two runners from 5 =[tex]^5P_2=\frac{5!}{(5-2)!}=5\times4=20[/tex]
Then, the probability that Alice is chosen first and Emma is chosen second is given by :-
[tex]\text{P(Alice is chosen first and Emma is chosen second )}=\frac{1}{20}[/tex]
