iluvtwilight268 iluvtwilight268
  • 15-07-2017
  • Mathematics
contestada

Find the gradients of the lines that pass through the point (1,7) and are tangent to the parabola y = (2−x)(1+3x).

Respuesta :

eziwest
eziwest eziwest
  • 15-07-2017
y=(2-x) (1+3x)
This is vertical. and that should be 4x=1
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Sxerks Sxerks
  • 15-07-2017
[tex]y = (2-x)(1+3x)[/tex]
[tex] = 2 + 6x - x - 3x^{2}[/tex]
[tex] = 2 + 5x - 3x^{2}[/tex]

[tex]\frac{dy}{dx} = m = 5 - 6x[/tex]

At x = 1:
[tex]\frac{dy}{dx} = m = 5 - 6 = -1[/tex]

[tex]y - 7 = -(x - 1)[/tex]
[tex]y = -x + 8[/tex]
[tex]\therefore y = 8 - x[/tex]
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