krussell1984
krussell1984 krussell1984
  • 04-07-2017
  • Mathematics
contestada

how many terms are in, 1+3+5+7+...+997

Respuesta :

Thales
Thales Thales
  • 04-07-2017
You know how many numbers are in 1+2+3+4+...+997, the answer is of course 997. Comparing your sequence to this one, you're essentially removing every other number, so you have 1, remove 2, then 3, remove 4 etc. all the way up to 995, remove 996. Up to that point you have removed half the numbers, so you have 996/2 = 498 numbers. You also have 997, so the total number of terms in the sequence is 499.
Answer Link

Otras preguntas

The best way to avoid cash flow problems is A. borrowing less. B. downsizing. C. constant marketing. D. regular saving.
what is 6.12 as a fraction
draw an array then write a fact family to describe your array
Which statements are correct interpretations of this graph? Choose exactly two answers that are correct. A. There are 2 g of dietary fiber in every 3 tomatoes.
Please help, Using the rules of electricity, explain why peoples' hair stands up when a balloon is rubbed on their head.
Unlike clip art, you cannot resize a photograph using the mouse.true or false
What are many things that Nero the Emperor did?
An atom of the element zinc has an atomic number of 30 and a mass number of 65. How many protons does an uncharged zinc atom have? 30 35 65 95
which of the actions is more appropriate for dealing with major frustrarions than with minor frustration a. gaining control of your life b. blowing of steam. c.
can 3/42 be simplified?