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  • 14-06-2017
  • Chemistry
contestada

What is the pOH of a KOH solution that has [OH− ] = 5.81 × 10−3 M?

Respuesta :

dec77cat dec77cat
  • 14-06-2017
pOH = -lg[OH⁻]

pOH = -lg(5.81*10⁻³) = 2.24
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BarrettArcher BarrettArcher
  • 12-03-2019

Answer : The pOH of KOH solution is, 2.235

Solution : Given,

Concentration of [tex]OH^-[/tex] ion = [tex]5.81\times 10^{-3}M[/tex]

As we know that,

[tex]pOH=-\log [OH^-][/tex]

Now put the value of [tex]OH^-[/tex] ion concentration, we get the pOH.

[tex]pOH=-\log (5.81\times 10^{-3}M)[/tex]

[tex]pOH=2.235[/tex]

Therefore,the pOH of KOH solution is, 2.235

Answer Link

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