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14-06-2017
Chemistry

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How many moles of hydrogen atoms are present in 25.0 g of water?

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dec77cat dec77cat

14-06-2017

m(H₂O)=25.0 g
M(H₂O)=18.02 g/mol

n(H₂O)=m(H₂O)/M(H₂O)

n(H)=2n(H₂O)=2m(H₂O)/M(H₂O)

n(H)=2*25.0/18.02=2.775 mol

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