sreep71
sreep71
12-03-2015
Mathematics
contestada
What is the square root of 12.25
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Аноним
Аноним
20-03-2015
[tex]\sqrt{12.25}=\sqrt{12\frac{1}{4}}=\sqrt{\frac{12\cdot4+1}{4}} =\sqrt{\frac{49}{4}}=\frac{\sqrt{49}}{\sqrt4}=\boxed{\frac{7}{2}=3\frac{1}{2}=3.5}[/tex]
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