jacari9
jacari9
15-04-2017
Mathematics
contestada
The question is to solve: 72 = logx
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jdoe0001
jdoe0001
15-04-2017
[tex]\bf 72=log(x)\iff 72=log_{10}(x)\\\\ -----------------------------\\\\ \textit{cancellation rules}\\\\ log_{{ a}}{{ a}}^x\implies x\qquad \qquad {{ a}}^{log_{{ a}}x}=x\impliedby \textit{let's use this one}\\\\ -----------------------------\\\\ 10^{72}=10^{log_{10}(x)}\implies 10^{72}=x[/tex]
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Sxerks
Sxerks
15-04-2017
Answer: [tex]x = 10^{72}[/tex]
Explanation: Logarithms are usually written in base of 10, unless otherwise specified.
So, we can rewrite the logarithm as:
[tex]72 = log_{10} x[/tex]
Rewriting it in exponent form, we get:
[tex]x = 10^{72}[/tex]
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