xclusiveprxncess
xclusiveprxncess xclusiveprxncess
  • 13-04-2017
  • Mathematics
contestada

What could this be? Someone please help

What could this be Someone please help class=

Respuesta :

Аноним Аноним
  • 13-04-2017
first you need to solve both inequalities system
p+m<= 20
so p<= 20 - m
substitute p<= 20 - m into 5p+ 10m< = 120

5p+ 10m< = 120
5(20-m)+ 10m< = 120
100 - 5m + 10m <= 120
5m <= 20
m<= 4

p<= 20 - m
p<= 20 -4
p<= 16

now you can find variable and non-variable solutions (p,m)

variable:
(15,3)
(10,-5)


Non-variable:
(0,10)
(20,1)
(5,5)
(0,15)

Answer Link
jarrod012299
jarrod012299 jarrod012299
  • 13-04-2017
first you need to solve both inequalities system
p+m<= 20
so p<= 20 - m
substitute p<= 20 - m into 5p+ 10m< = 120

5p+ 10m< = 120
5(20-m)+ 10m< = 120
100 - 5m + 10m <= 120
5m <= 20
m<= 4

p<= 20 - m
p<= 20 -4

Answer Link

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