nubunnebRaudy7 nubunnebRaudy7
  • 15-03-2017
  • Chemistry
contestada

A common cooking vinegar is 5.0% acetic acid (ch3cooh. how many molecules of acetic acid are present in 41.9 g vinegar?

Respuesta :

MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 23-03-2017
To calculate the number of molecules ch3cooh in a given amount of vinegar, we first need to determine the amount of ch3cooh in the solution by multiplying the percent ch3cooh with the sample amount. Then, convert g to moles and use avogadro's number. We do as follows:

41.9 g vinegar solution ( .05 g 
ch3cooh / g vinegar solution ) (1 mol / 60.05 g ) ( 6.022x10^23 g / 1 mol ) = 2.1x10^22 molecules ch3cooh
Answer Link

Otras preguntas

What is the mass of 0.11 moles of sodium carbonate, Na2CO3?
please fill the gaps (50points)​
Which of the following retirement vehicles provide income tax-advantages? (check all that apply) A. 403(b)B. Mutual FundC. 401(k)D. Roth IRAE. IRA​
Based on the family the graph below belongs to, which equation could represent the graph?
Whats the correct answer answer asap for brainlist
A block of aluminium has a volume of 5.0 cm³ and a mass of 13.5 g. Calculate the density of the aluminium. Give your answer in g/cm³.​
I just need the answers I’ve been procrastinating for hours
Why is the angle of elevation for two parasailing boats traveling at the same speed
The tree diagram represents an experiment consisting of two trials P(A andC)=
need help with this question. ​