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14-03-2017
Mathematics

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solve for x

[tex](3^{2x-1})(3^2)=(3x^{2+x})(3^x)[/tex]

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LammettHash LammettHash

17-03-2017

[tex]3^{2x-1}3^2=3^{2+x}3^x[/tex]
[tex]3^{2x-1+2}=3^{2+x+x}[/tex]
[tex]3^{2x+1}=3^{2x+2}[/tex]

Because the bases are identical, so must be the exponents, meaning you have

[tex]2x+1=2x+2[/tex]

but this has no solution.

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