Answer:
Explanation:
The given force is:
[tex]F=(2.2N)x+(1.0N)y[/tex]
Part A
If the displacement of the dog is:
d = (0.29m)x
The work done is the dot product of the force and displacement
[tex]\begin{gathered} W=F.d \\ \\ W=\text{ \lparen2.2\rparen\lparen0.29\rparen+\lparen1.0\rparen\lparen0\rparen} \\ \\ W=0.638Joules \end{gathered}[/tex]
Part B
If the displacement of the dog is:
d = (0.29m)y
The workdone will be calculated as:
[tex]\begin{gathered} W=F.d \\ \\ W=(2.2)(0)+(1.0)(0.29) \\ \\ W=0.29\text{ Joules} \end{gathered}[/tex]
