sydneyleduc sydneyleduc
  • 12-02-2017
  • Mathematics
contestada

Write the complex number in the form a + bi. 3(cos 270° + i sin 270°)

Respuesta :

sakethmalyala
sakethmalyala sakethmalyala
  • 12-02-2017
corresponds to the very bottom of the circle --- is equal to -3i
Answer Link
OrethaWilkison OrethaWilkison
  • 21-02-2019

Answer:

Given the complex number:  [tex]3(\cos 270^{\circ}+i \sin 270^{\circ})[/tex]

Let [tex]z=3(\cos 270^{\circ}+i \sin 270^{\circ})[/tex]

we have to write this complex number in the form of a+ib.

We know :

[tex]\cos 270^{\circ} = 0[/tex]

[tex]\sin 270^{\circ} = -1[/tex]

Then;

[tex]z = 3(0+i(-1)) = 3(0-i)[/tex]

or

[tex]z = 0-3i[/tex]

Therefore, the given complex number in the form of a+ib is, 0-3i

Answer Link

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