Emily20072004
Emily20072004 Emily20072004
  • 13-05-2022
  • Mathematics
contestada

I need help! It is for a task.

I need help It is for a task class=

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loneguy
loneguy loneguy
  • 13-05-2022

[tex]\text{Given that,}~ q =-4~ \text{and}~ g =1\\\\~~~~~\dfrac{6q}{4}(6g) -q\\\\\\=\dfrac{6(-4)}{4}(6\cdot 1) - (-4)\\\\\\=-6\cdot 6 +4\\\\\\=-36 +4 \\\\\\=-32[/tex]

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ven22514
ven22514 ven22514
  • 13-05-2022

Step-by-step explanation:

6q/4 (6g) - q

6(-4)/ 4 [6(1)] - (-4)

-24/4 (6) + 4

-6(6) + 4

-36 + 4

-32

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