The current in the series circuit across a 9.0 V potential difference is determined as 0.333 A.
Current in the series circuit
The current in the series circuit is determined by applying ohms law as shown below;
V = IR
where;
- I is the current
- R is equivalent resistance of the circuit
R = 12 Ω + 15 Ω = 27 Ω
I = V/R
I = 9/27
I = 0.333 A
Thus, the current in the series circuit across a 9.0 V potential difference is determined as 0.333 A.
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