Respuesta :

fieryanswererft

Answer:

[tex]\sf y' = \dfrac{x-7}{5}[/tex]

Explanation:

⇒ y = 5x + 7

⇒ 5x + 7 = y

⇒ 5x = y - 7

⇒ x = (y-7)/5

replace x with y

⇒ y' = (x-7)/5
  • y=5x+7

Take this and solve for x

  • 5x=y-7
  • x=y-7/5

Interchange y and x

  • y=x-7/5

So

The inverse is

[tex]\\ \rm\dashrightarrow y^{-1}(x)=\dfrac{x-7}{5}[/tex]