Answer:
[tex]S_{32}[/tex] = 140
Step-by-step explanation:
The sum of n terms of an AP is
[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] [ 2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
Here a₁ = 0.5 and d = a₂ - a₁ = 0.75 - 0.5 = 0.25 , then
[tex]S_{32}[/tex] = [tex]\frac{32}{2}[/tex] [ (2 × 0.5) + (31 × 0.25) ]
= 16(1 + 7.75)
= 16 × 8.75
= 140
