morain22 morain22

13-06-2021
Mathematics

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What are the center and radius of the circle defined by the equation x^2 + y^2 -6x + 8y + 21=0

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surjithayer10otahza surjithayer10otahza

13-06-2021

Answer:

Step-by-step explanation:

(x²-6x)+(y²+8y)=-21

(x²-6x+9)+(y²+8y+16)=-21+9+16

(x-3)²+(y+4)²=4

center=(3,-4),radius=√4=2

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