sdeajim sdeajim
  • 03-12-2016
  • Mathematics
contestada

what are the vertex focus and directrix of the parabola with the given equation
y=1/28(x-4)^2-5

Respuesta :

MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 13-12-2016
If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the y-axis, it has an equation of (x - h)^2 = 4p(y - k), where the focus is (h, k+p) and the directrix is y = k - p. So, we need to determine the values from the equation.

y=1/28(x-4)^2-5
(x-4)^2 = 28(y+5)
(h,k) = (4, -5)
p = 7

focus= 
(h, k+p) = 4,2
directrix = y = k - p = -12

Hope this answers the question.
Answer Link
applelulu
applelulu applelulu
  • 26-05-2019

The answer is:

vertex: (4,-5); focus: (4,2); directrix: y=-12

Answer Link

Otras preguntas

write four numbers that round to 700,000 when rounded to the nearest hundred thousand
what is the value the 1 in 214,278,216
calculate the average speed of spacecraft orbiting mars
For what value of a is a(2x+3)=9x+15+x an identity?
What was the source of Florence’s wealth and power?
A family uses 12,986.64 Swiss francs per year to pay a mortgage that requires US dollars. Approximately how much, in US dollars, does the family spend per month
what message might these frequent and violent changes leadership have sent to people living outside Roman Empire
Which factor most greatly limits the power of the US government? regular, free elections a sovereign government electing a chief executive a constitutio
Which area of geographical study focuses on examining landforms, soils, and bodies of water?
slove the equation 2x^2(6y^3) (2x^2 y)