Answer:
[tex] 76 \: {in}^{2} [/tex]
Step-by-step explanation:
Area of the figure = Are of square with side 8 in + 2 times the area of one triangle with base (8 - 5 = 3) 3 in and height 4 in
[tex] = {(8)}^{2} + 2 \times \frac{1}{2} \times 3 \times 4 \\ \\ = 64 + 12 \\ \\ = 76 \: {in}^{2} [/tex]
