Answer:
(14)The pH is 8.3 and is basic
(15) pOH = 11.0 The solution is acidic
Explanation:
(14) From the question,
pH = -log[H₃O⁺]............... Equation 1
Given: H₃O⁺ = 5.6×10⁻⁹ M
Substitute the value above into equation 1
pH = -log[5.6×10⁻⁹]
pH = 8.3
The pH is 8.25 and is basic.
(15)
pOH = -log[OH⁺]................ Equation 2
Given: [OH⁺] = 8.34×10⁻¹² M
Substitute into equation 2
pOH = -log[8.34×10⁻¹²]
pOH = 11.0 Hence the solution is acidic
