Answer:
x = - 3 ± 2[tex]\sqrt{3}[/tex]
Step-by-step explanation:
Given
2x² + 12x = 6 ( divide through by 2 )
x² + 6x = 3
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(3)x + 9 = 3 + 9
(x + 3)² = 12 ( take the square root of both sides )
x + 3 = ± [tex]\sqrt{12}[/tex] = ± 2[tex]\sqrt{3}[/tex] ( subtract 3 from both sides )
x = - 3 ± 2[tex]\sqrt{3}[/tex] ← exact solutions
