jjassal jjassal
  • 15-03-2021
  • Mathematics
contestada

h(j + i) - k5 + h
when h = 3, i = 4, j = 2, and k = 1
pls put how you did it

Respuesta :

savannahgibson3639
savannahgibson3639 savannahgibson3639
  • 15-03-2021

Answer:

16

Step-by-step explanation:

First you want to plug in all the numbers where the letters are

h ( j + i )- k(5) + h

3 ( 2 + 4 )- 1(5) + 3

After this step you will have to distribute the 3 outside the parenthesis. Which you do by multiplying everything in side the parenthesis by the outside number which is three.

6 + 12 - 1(5) + 3

Then you just follow PEMDAS to solve for the rest

6 + 12 - 5 + 3

18 - 5 + 3

13 + 3

16

Answer Link

Otras preguntas

The first bend made with a hicky should be about
describe the role of the nurse before nasogastric Tube feeding procedure​
Fill out the table of values given the system of equations. What is the solution to the system? y=x+1 y = 2x - 1 0 x+1 2 10 1 11 I 2x1 10 The solution to the sy
How does light function as a symbol in this section? How has that symbol changed, even if slightly (frankenstein ch. 11-13)
3 to the exponent of -3 is?
Solve for x in the inequality. -8x 4 < -4
Solve the inequality 5x+10y<40
5/3 + n = 4 1/4 what is n??
If (0, 4) is on the graph of f(x), what point must be on (4, 0)?
Please help!!! Will reward brainliest just please be right. I don't have many attempts left and I'm confused on how to calculate this. I already got the first p