Answer:
Step-by-step explanation:
the smallest length that the pen could be is the with x length => 209 sq ft
where the length is 8 feet more than the width.
so find that where x *( x+8) = 209
then [tex]x^{2}[/tex] + 8x - 209 = 0
using the quadratic equation I got 11
11* ( 11+8) =209
so that's the smallest it could be
so the width must be greater than 11 to make the pen greater than 209 sq ft. :)
