Answer:
Step-by-step explanation:
(cos³x)/(sin x)=cot x
(cos³ x)/(sin x)=(cos x)/sin x
sin x≠0
x≠0,π,2π
cos³x-cos x=0
cos x(cos²x-1)=0
either cos x=0,x=π/2 ,3π/2
or
cos²x-1=0
2 cos²x=2
1+cos 2x=2
cos 2x=1=cos2nπ,n=0,1,2
2x=2nπ
x=nπ
x=0,π,2π
But x≠0,π,2π
so x=π/2,3π/2
