Answer:
AB = 5[tex]\sqrt{2}[/tex]
Step-by-step explanation:
Calculate the distance using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = A(6, 3) and (x₂, y₂ ) = B(- 1, 4)
AB = [tex]\sqrt{(-1-6)^2+(4-3)^2}[/tex]
= [tex]\sqrt{(-7)^2+1^2}[/tex]
= [tex]\sqrt{49+1}[/tex]
= [tex]\sqrt{50}[/tex]
= 5[tex]\sqrt{2}[/tex] ← exact value
≈ 7.07 ( to 2 dec. places )
