The temperature : 154.73 K
Further explanation
Given
mass = m = 5 g of Cl2
P = 900 mmHg = 1,18421 atm
V = 0.75 L
Required
Temperature
Solution
mol Cl2 = mass : MW = 5 : 71 = 0.07
Ideal gas law : PV = nRT
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.082 L.atm / mol K
T = temperature, Kelvin
T = PV/nR
Input the value :
T = 1.18421 x 0.75 / 0.07 x 0.082
T = 154.73 K
