Answer:
128
Step-by-step explanation:
There is a common difference between consecutive terms, that is
11 - 2 = 20 - 11 = 9
This indicates the sequence is arithmetic with n th term
[tex]t_{n}[/tex] = t₁ + (n - 1)d
where t₁ is the first term and d the common difference
Here t₁ = 2 and d = 9 , thus
t₁₅ = 2 + (14 × 9) = 2 + 126 = 128
