lolmariana08 lolmariana08

12-11-2020
Mathematics

contestada

Rewrite the function by completing the square.
h(x) = 4x2 + 4x + 1

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hnori22003 hnori22003

12-11-2020

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[tex]h(x) = 4 {x}^{2} + 4x + 1 [/tex]

[tex]h(x) = ({2x + 1})^{2} [/tex]

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