First, we must determine b using slope-intercept form*, the given point, and the given slope.
[tex]-4 = -\frac{1}{3}(-9) + b\\\\-4 = -3 + b\\\\-1 = b[/tex]
Second, we need to set up the equation of the line in slope-intercept form.
[tex]y = -\frac{1}{3}x - 1[/tex]
Third, we convert the above equation to STANDARD FORM**.
[tex]y = -\frac{1}{3}x - 1\\\\\frac{1}{3}x + y = -1[/tex]
We now have our equation: [tex]\frac{1}{3}x - y = -1[/tex]
*Slope-intercept form: y = mx + b
**Standard form: ax + by = c
