briennegraber4328 briennegraber4328
  • 14-09-2020
  • Chemistry
contestada

given that 32.0g sulphur contains 6.02×10^23 sulphur atoms,how many atoms are there in 2.70g of aluminum​

Respuesta :

lawalj99 lawalj99
  • 18-09-2020

Answer:

6.022 × 10²² atoms

Explanation:

Generally 1 mol of any element contains 6.02×10^23  atoms. The number 6.022 × 10²³ is known as Avogadro's number.

Mass of Aluminium = 2.70g

Molar mass = 27g/mol

Number of moles = Mass / Molar mass = 2.70 / 27 = 0.1 mol

1 mol =  6.022 × 10²³

0.1 mol = x

x = 6.022 × 10²³ * 0.1 = 6.022 × 10²² atoms

Answer Link

Otras preguntas

someone help me pls i need an answer
Early Americans were known as a dependent on?
What is the asymptote of the graph of g(x)=3x+6?
b) A dealer bought a laptop for Rs 45,000 and sold it to a retailer at 12% profit. The retailer again sold it to a customer at 25% profit. How much did the cust
for each function, what is the output of the given input? For f(x) = -5x +1, find f(3). a. -16 b. -14 c. -2 d. 16
whats the equation of x2=5
pleaseeeeee helpppp:(
In a typical corporate organizational structure: Multiple Choice the vice president of finance reports to the chair of the board. the controller reports to the
This photo of her_____ on holiday last year(take)​
Definition of slopes on a volcano