Answer:
[tex]f^{-1}[/tex](x) = [tex]\frac{1}{9}[/tex] x + 8
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = 9(x - 8) ← divide both sides by 9
[tex]\frac{y}{9}[/tex] = x - 8 ( add 8 to both sides )
[tex]\frac{y}{9}[/tex] + 8 = x
Change y back into terms of x with x = [tex]f^{-1}[/tex](x) , thus
[tex]f^{-1}[/tex](x) = [tex]\frac{1}{9}[/tex] x + 8
