Respuesta :

Answer:

Area=128

Step-by-step explanation:

p=8[tex]\sqrt{2}[/tex]

A=p^2

put value of p

A= (8[tex]\sqrt{2}[/tex])power2

A= (8^2* [tex]\sqrt{2}[/tex]^2)

A=64 * 2             (square root of 2 will be cancel by power 2)

A= 128  

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