Answer:
The horizontal component of the force, Fâ‚“ = 63.64 N
The vertical component of the force, [tex]F_y[/tex] = Â 63.64 N
Explanation:
Given;
magnitude of the force, F = 90 N
angle between the handle and the ground, θ = 45°
The horizontal component of the force, Fₓ = Fcosθ
Fâ‚“ = 90 x cos45
Fâ‚“ = 63.64 N
The vertical component of the force, [tex]F_y = Fsin \theta[/tex]
[tex]F_y[/tex] = 90 sin45
[tex]F_y[/tex] = 63.64 N
Therefore, the horizontal  and vertical components of the force is 63.64 N.