Respuesta :

Lightx

Answer:

[tex] a=\pm 4[/tex]

Step-by-step explanation:

[tex] M^2= \begin{bmatrix} a^2 +1 & 0 \\ 0 & a^2+1 \end{bmatrix} =17 \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}\\[/tex]

Equate the terms to get:

$a^2+1=17$

$\implies a^2=16 \implies a= \pm 4$