bellaisamaya05 bellaisamaya05
  • 15-06-2020
  • Mathematics
contestada

Find the value of sinY

Find the value of sinY class=

Respuesta :

Leora03
Leora03 Leora03
  • 17-06-2020

Answer:

[tex] \frac{63}{65} [/tex]

Step-by-step explanation:

Please see the attached picture.

Let's find the value of the opposite side, XZ.

Applying Pythagoras' Theorem,

(XZ)² +(XY)²= (ZY)²

(XZ)² +16²= 65²

(XZ)²= 4225 -256 (bring constant to 1 side)

(XZ)²= 3969 (simplify)

Square root both sides,

XZ= [tex] \sqrt{3969} [/tex]

XZ= 63 (simplify)

sinY

= XZ/ ZY

[tex] = \frac{63}{65} [/tex]

Ver imagen Leora03
Answer Link
scottrn9696 scottrn9696
  • 23-06-2022

Answer:

63/65

Step-by-step explanation:

Answer Link

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