lilliegchilds lilliegchilds
  • 12-05-2020
  • Mathematics
contestada

Please could I have some help :)

Please could I have some help class=

Respuesta :

mirai123
mirai123 mirai123
  • 12-05-2020

Answer:

a) [tex]$\frac{\sqrt{15} }{\sqrt{5}}\cdot \frac{\sqrt{5} }{\sqrt{5}}=\frac{\sqrt{75} }{5}=\frac{5\sqrt{3}}{5}=\sqrt{3} $[/tex]

or simply

[tex]$\frac{\sqrt{15}}{\sqrt{5}}=\sqrt{\frac{15}{5}}=\sqrt{3}$[/tex]

b)[tex]$\frac{\sqrt{3}\:}{\sqrt{6}} \cdot \frac{\sqrt{6}\:}{\sqrt{6}}=\frac{\sqrt{18} }{6}=\frac{3\sqrt{2} }{6}=\frac{\sqrt{2} }{2} $[/tex]

or

[tex]$\frac{\sqrt{3}}{\sqrt{6}}=\sqrt{\frac{3}{6}}=\sqrt{\frac{1}{2}}$[/tex]

[tex]$\sqrt{\frac{1}{2}}=\frac{\sqrt{2} }{2} $[/tex]

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