Respuesta :

Suppose that:
let f(x) = e^x 

Suppose:
 a = 0 
Now we are finding f(a):
f(a) = f(0) = 1 

f '(x) = e^x 
Now we are finding f '(a):
f '(a) = f '(0) = 1 
Putting the formula:
L(x) = f(a) + f '(a)( x - a) 

L(e^0.01) = 1 + 1(0.01 - 0) 

= 1.01 is the answer

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