Answer:
[tex]x \geqslant - 5[/tex]
Step-by-step explanation:
first subtract 1 from both sides of inequality then multiply both sides with x+2 and lastly leave x alone by subtracting 3 from boths sides and add x to both sides[tex] \frac{3}{x + 2} + 1 \geqslant 0 \\ \frac{3}{x + 2} \geqslant - 1 \\ 3 \geqslant ( - 1) \times (x + 2) \\ 3 \geqslant - x - 2 \\ x \geqslant - 5[/tex]
