omargomez8948 omargomez8948
  • 04-04-2020
  • Mathematics
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The graph of F(X)= (6-4X)^2/2X^2-5X+12 HAS A HORIZONTAL ASYMPTOTE AT Y=

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amna04352
amna04352 amna04352
  • 04-04-2020

Answer:

Y = 8

Step-by-step explanation:

(6-4X)²/[2X²-5X+12]

[36 - 48X + 16X²]/[2X² - 5X + 12]

Y = 16/2

Y = 8

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Idea63
Idea63 Idea63
  • 06-10-2020

Answer: 8

Step-by-step explanation:

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