Kindlyevil Kindlyevil

13-07-2016
Mathematics

contestada

make a the subject of

a+3=[tex] \frac{2a+7}{r} [/tex]

Respuesta :

konrad509 konrad509

13-07-2016

[tex]a+3=\dfrac{2a+7}{r}\\ r(a+3)=2a+7\\ ar+3r=2a+7\\ ar-2a=7-3r\\ a(r-2)=7-3r\\ a=\dfrac{7-3r}{r-2}\\ a=-\dfrac{3r-7}{r-2} [/tex]

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