Respuesta :

mariamikayla
[tex]\frac{1}{3}h -4(\frac{2}{3}h-3^{(3})=\frac{2}{3}h-6^{(3} \\\\ \frac{h}{3} -4*\frac{2h-9}{3}=\frac{2h-18}{3} \\\\ h-4(2h-9)=2h-18 \\\\ h-8h+36=2h-18 \\\\ -7h+36=2h-18 \\\\ -7h-2h=-18-36 \\\\ -9h=-54 \\\\ \boxed{h=\frac{-54}{-9}=6}[/tex]
luana
[tex]\frac{1}{3}h-4(\frac{2}{3}h-3)=\frac{2}{3}h-6\ \ \ \ |multiply\ by\ 3\\\\ h-4(2h-9)=2h-18\\\\ h-8h+36=2h-18\\\\ -7h+36=2h-18\ \ \ |subtract\ 2h\\\\ -9h+36=-18\ \ \ |subtract\ 36\\\\ -9h=-54\ \ \ |divide\ by\ -9\\\\ h=6[/tex]

Otras preguntas