sabee2c4ualvillyya sabee2c4ualvillyya

15-06-2016
Mathematics

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an = cos(npi/2). If convergent find limit of sequence?

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HomertheGenius HomertheGenius

21-06-2016

The sequence is: cos(π/2), cos (π ), cos (3π/2), cos ( 2π ),...
or: 0,-1,0,1,0,-1,0,1,... Since cos (nπ/2) oscillates between -1 and 1 as n tends to infinity, this sequence is divergent (limit does not exist).

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