14-12-2019
Mathematics

contestada

2y+7<13 or -3y-2_<10

Respuesta :

14-12-2019

[tex]

2y+7 < 13 \vee -3y-2 < 10 \\

2y < 6 \vee -3y < 12 \\

y < 3 \vee y < -4 \Longrightarrow y\in(-\infty, 3)

[/tex]

Hope this helps.

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