seanasia1 seanasia1
  • 14-11-2019
  • Mathematics
contestada

Can someone help me please

Can someone help me please class=

Respuesta :

jitumahi456 jitumahi456
  • 18-11-2019

Answer:

Maximum value of  [tex]C=39[/tex]

Step-by-step explanation:

[tex]C=3x+4y[/tex]

For the above equation the given constraints are:

[tex]x\geq2\\x\leq5\\y\geq1\\y\leq6[/tex]

So, we can see the maximum value for  [tex]x[/tex] and [tex]y[/tex] are:

[tex]x=5\\y=6[/tex]

We plugin the maximum values in the given equation:

[tex]C=3(5)+4(6)\\C=(3\times5) +(4\times6)\\C=15+24\\C=39[/tex]

∴ Maximum value of  [tex]C=39[/tex]

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