Answer:
[tex]\large \boxed{\boxed{p>-4}}}[/tex]
Step-by-step explanation:
[tex]3p-2\geq4\ or\ 7p>-28\\\\(1)\\3p-2\geq4\qquad\text{add 2 to both sides}\\3p-2+2\geq4+2\\3p\geq6\qquad\text{divide both sides by 3}\\\dfrac{3p}{3}\geq\dfrac{6}{3}\\\boxed{p\geq2}\\\\(2)\\7p>-28\qquad\text{divide both sides by 7}\\\dfrac{7p}{7}>-\dfrac{28}{7}\\\boxed{p>-4}\\\\\text{From (1) and (2) we have:}\\\\p\geq2\ or\ p>-4\Rightarrow \boxed{\boxed{p>-4}}[/tex]
