timmy61 timmy61
  • 11-10-2019
  • Mathematics
contestada

what is an equation of the line that passes through (6,-1) and is parallel to the line x-3y = 3

Respuesta :

Bladewolf463 Bladewolf463
  • 11-10-2019

Answer:

a=-3

Step-by-step explanation:

find the equation of the line parallel to the line x−3y=3 passing through the point (6,−1).

The equation of the line in the slope-intercept form is y=x3−1.

The slope of the parallel line is the same: m=13.

So, the equation of the parallel line is y=x3+a.

To find a, we use the fact that the line should pass through the given point: −1=(13)⋅(6)+a.

Thus, a=−3.

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