enriequedaim enriequedaim
  • 14-09-2019
  • Mathematics
contestada


[tex]y = \frac{1}{2} + \frac{w}{3} [/tex]
express w in terms of y ​

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tramserran
tramserran tramserran
  • 14-09-2019

Answer:  [tex]\bold{w=\dfrac{6y-3}{2}}[/tex]

Step-by-step explanation:

Isolate w by performing the following steps

  • Multiply by 6 on both sides to clear the denominator
  • Subtract 3 from both sides
  • Divide both sides by 2

[tex]y=\dfrac{1}{2}+\dfrac{w}{3}\\\\\\6\bigg[y=\dfrac{1}{2}+\dfrac{w}{3}\bigg]\quad \implies \quad 6y=3+2w\\\\\\6y-3=3-3+2w\quad \implies \quad 6y-3=2w\\\\\\\dfrac{6y-3}{2}=\dfrac{2w}{2}\quad \implies \quad \large\boxed{\dfrac{6y-3}{2}=w}[/tex]

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