Answer:
[tex]12 \sqrt{5} \: - 6 \sqrt{2} [/tex]
Step-by-step explanation:
first you need to simply the √20
which is
[tex] \sqrt{4} \: \times \sqrt{5} [/tex]
[tex] \sqrt{2} \: \times \sqrt{2} \: \times \sqrt{5} [/tex]
[tex]2 \sqrt{5} [/tex]
again simplifying √8
[tex] \sqrt{4} \: \times \sqrt{2} [/tex]
[tex]2 \sqrt{2} [/tex]
so adding to the general equation you get
[tex]6 \times 2 \sqrt{5} \: - 3 \times 2 \sqrt{2} [/tex]
=
[tex]12 \sqrt{5} \: - 6 \sqrt{2} [/tex]
